Respuesta :
Answer:
30 seconds
Explanation:
A = A02^-(t/hl)
--> ln(A/A0) = -(t/hl)ln2
solving for hl,
hl = -t x ln2 /ln(A/A0)
= -(60 min)xln2/ln(50/200)
= 0.5 min or 30 seconds
The amount of half-life cycles that have occurred is mathematically given as
HL=30sec
What is the amount of half-life cycles that have occurred?
Question Parameter(s):
If a sample of radioactive isotopes takes 60 minutes
to decay from 200 grams to 50 grams
Generally, the equation for the half-life cycle is mathematically given as
A = A02^-(t/hl)
Therefore
HL = -t * ln2 / ln(A/A0)
HL= -(60 min)xln2/ln(50/200)
HL=30
In conclusion, the number of half-live
HL=30
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