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the diagram above shows a uniform metre rule, X Y which is balance horizontally at the 90cm mark, when a mass of 0.4kg is suspended from Y. what is the mass of the metre rule​

the diagram above shows a uniform metre rule X Y which is balance horizontally at the 90cm mark when a mass of 04kg is suspended from Y what is the mass of the class=

Respuesta :

Answer:

0.1 Kg

Explanation:

Please see attached photo for explanation.

In the attached photo, M is the mass of the metre rule.

From the attached photo,

Anticlock wise moment = M × 40

Clockwise moment = 0.4 × 10

Anticlock wise moment = Clockwise moment

M × 40 = 0.4 × 10

M × 40 = 4

Divide both side by 40

M = 4 / 40

M = 0.1 Kg

Thus, the mass of the metre rule is 0.1 Kg

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