Write the standard form of the equation of the circles that passes through (0, 3) with its center at (0,0)

Respuesta :

Answer:

[tex]x^2+y^2=9[/tex]

Step-by-step explanation:

Equation of a circle (when centred at the origin):

[tex]x^2+y^2=r^2[/tex] where r is the radius of the circle

Plug in the point (0,3) to solve for the radius squared

[tex]0^2+3^2=r^2\\9=r^2[/tex]

Plug r² back into the original equation

[tex]x^2+y^2=9[/tex]

I hope this helps!