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Solve for × and write answer in interval notation.
[tex] \frac{1}{x + 1} \geqslant \frac{3}{x - 2} [/tex]
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Respuesta :

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Answer:

( -∞, -2.5] ∪ (-1, 2)

Step-by-step explanation:

1/(x + 1) ≥ 3/(x - 2)

x - 2 ≥ 3(x + 1)

x - 2 ≥ 3x + 3

x - 3x ≥ 3 + 2

-2x ≥ 5

x ≤ -2.5

Interval notation:

( -∞, -2.5] ∪ (-1, 2)

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