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the potential difference between two points, a and b, in an electric field is 2.00 volts. the energy required to move a charge of 8.00x10^-19 coulomb from point a to point b is

help the potential difference between two points a and b in an electric field is 200 volts the energy required to move a charge of 800x1019 coulomb from point a class=

Respuesta :

DynamoPrince2612

Answer:

1.60 x 10^-18 J

Explanation:

we know that, Work done = Voltage x Charge,

hence we get as,

Energy = V x Q

E = 2 x (8.0 * 10^-19)

==> E = 16 x 10^-19

=> E = 16/10 x 10^-18

==> E = 1.60 x 10^-18 J

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