Given:
Radius of the cylinder = 2 cm
Height of the cylinder = 3 cm
To find:
The surface area of the cylinder.
Solution:
The surface area of a cylinder is:
[tex]A=2\pi rh+2\pi r^2[/tex]
Where, r is the radius and h is the height of the cylinder.
Putting [tex]r=2,h=3,\pi = 3.14[/tex], we get
[tex]A=2(3.14)(2)(3)+2(3.14)(2)^2[/tex]
[tex]A=37.68+25.12[/tex]
[tex]A=62.8[/tex]
Therefore, the surface area of the cylinder is 62.8 square cm.
