Respuesta :
Note: Consider we need to find the equation of the line because the question statement is missing.
Given:
A line passes through the point (-10,-4) has a slope of [tex]-\dfrac{1}{2}[/tex].
To find:
The the equation of the line.
Solution:
The point slope form of a line is:
[tex]y-y_1=m(x-x_1)[/tex]
Where, m is the slope of the line and [tex](x_1,y_1)[/tex] is the point on the line.
A line passes through the point (-10,-4) has a slope of [tex]-\dfrac{1}{2}[/tex]. So, the equation of the line is:
[tex]y-(-4)=-\dfrac{1}{2}(x-(-10))[/tex]
[tex]y+4=-\dfrac{1}{2}(x+10)[/tex]
[tex]y+4=-\dfrac{1}{2}x-5[/tex]
Subtract 4 from both sides, we get
[tex]y+4-4=-\dfrac{1}{2}x-5-4[/tex]
[tex]y=-\dfrac{1}{2}x-9[/tex]
Therefore, the equation of the line is [tex]y=-\dfrac{1}{2}x-9[/tex]
