Given:
The quadratic equation is :
[tex]16x^2-20x-6=0[/tex]
To find:
The quadratic formula for the given equation after substituting the values.
Solution:
If a quadratic equation is [tex]ax^2+bx+c=0[/tex], then the quadratic formula is:
[tex]x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]
We have,
[tex]16x^2-20x-6=0[/tex]
In this equation, [tex]a=16,b=-20,c=-6[/tex].
Substituting [tex]a=16,b=-20,c=-6[/tex] in the above formula, we get
[tex]x=\dfrac{-(-20)\pm \sqrt{(-20)^2-4(16)(-6)}}{2(16)}[/tex]
Therefore, the required quadratic formula for the given equation after substituting the values is [tex]x=\dfrac{-(-20)\pm \sqrt{(-20)^2-4(16)(-6)}}{2(16)}[/tex].
