Answer:
1.08827 x 10^3 g.
Explanation:
The equation for the reaction is:
2LiOH + CO2 ----> Li2CO3 + H2O
Using the molar masses:
CO2 = 12.011 + 2* 16 = 44.011.
LiOH = 6.94 + 1.008 + 16 = 23.948
S0 44.011 of CO2 reacts with 2*23.948 g of LiOH
1.00 *10^3 g CO2 reacts with 2*23.948 * 1.00 *10^3 / 44.011
= 1088.27 g LiOH.