Answer:
[tex]6.8 molH_2O[/tex]
Explanation:
Hello there!
In this case, for this balanced chemical reaction about the combustion of methane, it is possible for us to inspect the 2:2 mole ratio of water to oxygen as given for their coefficients in the balanced chemical reaction.
In such a wat, given 6.8 moles of oxygen, we can easily obtain the produced moles of water by applying the aforementioned mole ratio as shown below:
[tex]6.8molO_2*\frac{2molH_2O}{2molO_2}\\\\6.8 molH_2O[/tex]
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