Answer:
1.3 M/s
Explanation:
Step 1: Given data
- Initial amount of methane (ni): 8.0 mol
- Final amount of methane (nf): 0 mol (it reacts completely)
- Volume of the container (V): 2.00 L
Step 2: Calculate the average rate of consumption of methane
Methane burns in excess oxygen according to the following equation.}
CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O
We can calculate the average rate of consumption of methane (r) using the following expression.
r = - Δn/V × t = - (nf- ni) / V × t
r = - (0 mol - 8.0 mol) / 2.00 L × 3.2 s = 1.3 M/s
