A rental car company charges $80 per day to rent a car and $0.10 for every mile driven. Alyssa wants to rent a car, knowing that: She plans to drive 150 miles. She has at most $300 to spend. Which inequality can be used to determine xx, the maximum number of days Alyssa can afford to rent for while staying within her budget?

Respuesta :

Answer:

400

Step-by-step explanation:

Car A costs 80d + 0.25m, where d is days and m is miles. Car B costs 100d + 0.10m. If you plug in 3 for d and make the equations equal, you get 240 + 0.25m = 300 + 0.10m. Combining like terms gives you 0.15m = 60, and dividing gives you m = 400.

fichoh

Using the inequality concept, the expression which models the maximum number of days in which she can rent the car is 80x + 15 ≤ 300

  • Maximum amount to spend = 300
  • Fixed charge per day $80
  • Charge per mile = $0.10

The inequality which represents the number of days Can be expressed thus :

(Charge per day × number of days) + (charge per mile × number of miles) ≤ 300

  • 80x + 0.10 × 150 ≤ 300

  • 80x + 15 ≤ 300

Hence, the required inequality expression is 80x + 15 ≤ 300

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