Answer:
The volume of can A is half the volume of can B.
Step-by-step explanation:
Given
Can A and Can B
Required
The true statement
For Can A, we have:
[tex]h =8[/tex]
[tex]r = 0.5[/tex]
The volume is:
[tex]Volume = \pi r^2h[/tex]
This gives:
[tex]V_A = \pi * 0.5^2 * 8[/tex]
[tex]V_A = \pi * 2[/tex]
[tex]V_A = 2\pi[/tex]
For Can B, we have:
[tex]h =4[/tex]
[tex]r = 1[/tex]
The volume is:
[tex]Volume = \pi r^2h[/tex]
This gives:
[tex]V_B = \pi * 1^2 * 4[/tex]
[tex]V_B = \pi * 4[/tex]
[tex]V_B = 4\pi[/tex]
So, we have:
[tex]V_A = 2\pi[/tex]
[tex]V_B = 4\pi[/tex]
By comparison, (d) is correct