A saturated solution of Ammonium Chloride is dissolved in 100 g of water.
If the saturated solution is cooled from 50°C to 30°C, how many grams of
precipitate will be formed?

All we need is to read off the solubility curve attached to this answer. The solubility curve is a plot of solubility of a solute against temperature.

By reading off the solubility curve, we can know the mass of precipitate that crystallizes out as the solution is cooled from 50°C to 30°C.

From the solubility curve;

Mass of Ammonium Chloride dissolved at 50°C = 50 g

Mass of Ammonium Chloride dissolve at 30°C = 40 g

Hence;

Mass of precipitate formed = 50 g - 40 g

Mass of precipitate formed = 10 g

A saturated solution of Ammonium Chloride is dissolved in 100 g of water. If the saturated solution is cooled from 50°C to 30°C, how many grams of precipitate will be formed?

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A saturated solution of Ammonium Chloride is dissolved in 100 g of water.
If the saturated solution is cooled from 50°C to 30°C, how many grams of
precipitate will be formed?