Answer: A volume of 50 mL of 10 M HCl must be used to create 100 mL of a 5 M solution.
Explanation:
Given: [tex]V_{1}[/tex] = ?, [tex]M_{1}[/tex] = 10 M
[tex]V_{2}[/tex] = 100 mL, [tex]M_{2}[/tex] = 5 M
Formula used to calculate the volume is as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]M_{1}V_{1} = M_{2}V_{2}\\10 M \times V_{1} = 5 M \times 100 mL\\V_{1} = 50 mL[/tex]
Thus, we can conclude that a volume of 50 mL of 10 M HCl must be used to create 100 mL of a 5 M solution.
