Suppose that you wish to construct a simple AC generator with an output of 12 V maximum when rotated at 60 Hz. A magnetic field of 0.050 T is available. If the area of the rotating coil is 100 cm2, how many turns are needed?

Respuesta :

Answer:

N = 63.6

Explanation:

The emf induced in AC generator is given as follows:

[tex]V = N\omega AB Sin\theta[/tex]

for maximum output, [tex]Sin\theta = 1[/tex]

[tex]V = N(2\pi f) AB[/tex]

where,

V = Maximum Output Voltage = 12 V

N = No. of Turns = ?

f = frequency = 60 Hz

A = Area of Coil = 100 cm² = 0.01 m²

B = Strength of Magnetic Field = 0.05 T

Therefore,

[tex]12\ V = N(2)(\pi)(60\ Hz)(0.01\ m^2)(0.05\ T)\\\\N = \frac{12\ V}{(2)(\pi)(60\ Hz)(0.01\ m^2)(0.05\ T)}[/tex]

N = 63.6