Answer:
The answer is "".
Explanation:
[tex]C_1=68.2 \ \frac{g}{L}\\\\V_2=1000.0 \ mL \\\\C_2=13.750 \ \frac{g}{L}\\\\V_1=?[/tex]
Using formula:
[tex]V_1=\frac{V_2 C_2}{C_1}\\\\[/tex]
[tex]=\frac{1000 \ mL \times 13.750 \ \frac{g}{L}}{68.2 \ \frac{g}{L}}\\\\= 201.61 \ mL[/tex]