Answer:
C: [tex]x^{2} +(y-3)^{2} =16[/tex]
Step-by-step explanation:
Recall that the equation of a circle is [tex](x-h)^2+(y-k)^2=r^2[/tex] where [tex](h,k)[/tex] is the center of the circle and [tex]r[/tex] is the radius of the circle. Observing the circle, we see that the center of the circle is [tex](0,3)[/tex] and the radius is [tex]r=4[/tex]. Therefore, your equation for the circle would be [tex]x^{2} +(y-3)^{2} =16[/tex].
