Answer:
0.1057
Step-by-step explanation:
We solve the above question using z score formula
z = (x-μ)/σ, where
x is the raw score = 32 oz
μ is the population mean = 33 oz
σ is the population standard deviation = 0.8oz
For x < 32 oz
z = 32 - 33/0.8
z = -1.25
Probability value from Z-Table:
P(x<32) = 0.10565
Approximately = 0.1057
Therefore, the proportion of packets that are underweight (i.e. Weight less than 32 oz.) are 0.1057.