Respuesta :

Answer:

[tex] {4x}^{2} + 8x - 5 \\ when \: x \: is \: \frac{3}{4} \\ = > 4 {( \frac{3}{4} )}^{2} + 8( \frac{3}{4} ) - 5 \\ = > \frac{13}{4} [/tex]