Answer:
[tex](x+5)^2+(y+5)^2=4[/tex]
Step-by-step explanation:
Hi there!
Equation of a circle: [tex](x-h)^2+(y-k)^2=r^2[/tex] where the circle is centered at (h,k) and r is the radius
1) Determine the center of the circle
On the graph, we can determine that the circle is centered at the point (-5,-5). Plug this into the equation:
[tex](x-(-5))^2+(y-(-5))^2=r^2\\(x+5)^2+(y+5)^2=r^2[/tex]
2) Determine the value of r²
In the graph, we can see that the radius of the circle is equal to 2 units. Therefore, the value of r² is 4. Plug this back into the equation:
[tex](x+5)^2+(y+5)^2=4[/tex]
I hope this helps!
