Answer:
t = 9.7 seconds
Step-by-step explanation:
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation as :
[tex]y=-16x^2+147x+80[/tex]
We need to find the time that the rocket will hit the ground, to the nearest 100th of second.
When the rocket hit the ground, So,
[tex]-16x^2+147x+80=0\\\\x=-0.515\ s\ and\ 9.70\ s[/tex]
Neglecting negative tim,
t = 9.7 s
Hence, it will hit the ground at 9.7 seconds.
