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if quadrilateral ABCD is a parallelogram, the measurement of angle B = 128 degrees, BC=24, and its area is 256find its perimeter

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birungjoel

Answer:

Area of parallelogram = ab sinx

a = Area/b sinx

a = 256/24 sin52

a = 10.67 sin52

a = 10.53

Perimeter  = 2(ab)

             P = 2 (10.53)(24)

             P = 252.72 x 2

             P = 505.44

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