Answer:
9.42 g
Explanation:
Step 1: Write the balanced equation
2 Al + 3 Cl₂ ⇒ 2 AICI₃
Step 2: Calculate the moles corresponding to 11.727 L of Cl₂
Since the conditions are not specified, we will assume Cl₂ is at standard temperature and pressure. At STP, 1 mole of Cl₂ occupies 22.4 L.
11.727 L × 1 mol/22.4 L = 0.524 mol
Step 3: Calculate the moles of Al needed to react with 0.524 moles of Cl₂
The molar ratio of Al to Cl₂ is 2:3. The moles of Al needed are 2/3 × 0.524 mol = 0.349 mol
Step 4: Calculate the mass corresponding to 0.349 moles of Al
The molar mass of Al is 26.98 g/mol.
0.349 mol × 26.98 g/mol = 9.42 g
