Answer:
(-1/12)(x-3)(x-8)
or
[tex]-\frac{x^2-11x+24}{12}[/tex]
Step-by-step explanation:
If something has x intercepts of (3,0) and (8,0) we can write the following
y=(x-3)(x-8)
To make the y intercept (0,-2) we will mulitply this by some constant, a
y=a(x-3)(x-8)
to solve for a set y= -2 and x=0
a(0-3)(0-8)= -2
a(-3)(-8)= -2
24a= -2
a= -1/12
Which means our final equation is
(-1/12)(x-3)(x-8)
which in standard form is equal to
[tex]-\frac{x^2-11x+24}{12}[/tex]
