Respuesta :

Answer:

x ∈ R(0=0)

Explanation:

Se la expresión [tex](a-b)^{2}=a^{2}-2ab+b^{2}[/tex]

[tex]x^{2}-4x=(x-2)^{2}-4\\x^{2}-4x=x^{2} -4x+4-4\\0 -4x=-4x+4-4\\0=4-4\\0=0[/tex]

La posición es verdadera para cualquier valor de X.

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