pandacoco678p16cll
contestada

If I have 18 liters of gas at a pressure of 88 atm, what will be the final pressure of the gas if the volume of the gas is decreased to 12 liters under constant pressure ? Show calculations.

Respuesta :

keijosalonen

Answer:  You meant in constant temperature?

Because temperature is not mentioned at the beginning.

I suppose temperature remains constant, otherwise

there is no enough data for solving the problem

Explanation: According Boyle´s law in constant temperature

pV = constant.  So p1V1 = p2V2   and pressure p2 = p1V1 /V2

= 88 atm · 18 l / 12 l =  132 atm.

samueladesida43

If I have 18 liters of gas at a pressure of 88 atm, the final pressure of the gas if the volume of the gas is decreased to 12 liters under constant pressure is 132atm.

HOW TO CALCULATE PRESSURE?

The pressure of gas at constant temperature can be calculated using Boyle's law equation as follows:

P1V1 = P2V2

Where;

  • P1 = initial pressure (88atm)
  • P2 = final pressure (?atm)
  • V1 = initial volume (18L)
  • V2 = final volume (12L)

The final pressure of the gas can be calculated as follows:

88 × 18 = 12 × P2

1584 = 12P2

P2 = 1584 ÷ 12

P2 = 132atm

Therefore, have 18 liters of gas at a pressure of 88 atm, the final pressure of the gas if the volume of the gas is decreased to 12 liters under constant pressure is 132atm.

Learn more about Boyle's law at: https://brainly.com/question/1437490

Otras preguntas