Answer:
[tex]f(g(5)) = 0[/tex]
Step-by-step explanation:
Given
[tex]f(x) = x+ 2[/tex]
[tex]g(x) = x^2 - 27[/tex]
Required
[tex]f(g(5))[/tex]
First, calculate [tex]f(g(x))[/tex]
We have:
[tex]f(x) = x+ 2[/tex]
Substitute [tex]g(x)[/tex] for x
[tex]f(g(x)) = g(x) + 2[/tex]
Substitute [tex]g(x) = x^2 - 27[/tex]
[tex]f(g(x)) = x^2 -27+ 2[/tex]
[tex]f(g(x)) = x^2 -25[/tex]
Substitute 5 for x
[tex]f(g(5)) = 5^2 -25[/tex]
[tex]f(g(5)) = 25 -25[/tex]
[tex]f(g(5)) = 0[/tex]
