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What is the molarity of a solution composed
of 4.27 g of potassium iodide (KI) dissolved in
enough water to make 0.304 L of solution?
Answer in units of M.

Respuesta :

maacastrobr

Answer:

0.0845 M

Explanation:

First we convert 4.27 grams of potassium iodide into moles, using its molar mass:

  • Molar Mass of KI = 166 g/mol
  • 4.27 g ÷ 166 g/mol = 0.0257 mol

Now we calculate the molarity of the solution, using the number of moles and the given volume:

  • Molarity = moles / liters
  • Molarity = 0.0257 mol / 0.304 L = 0.0845 M

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