Step-by-step explanation:
With the quadratic equation in this form: [tex]ax^2+bx+c=0[/tex]
Step 1: Find two numbers that multiply to give ac (in other words a times c), and add to give b.
Example: 2x^2 + 7x + 3
ac is 2×3 = 6 and b is 7
So we want two numbers that multiply together to make 6, and add up to 7
In fact 6 and 1 do that (6×1=6, and 6+1=7)
How do we find 6 and 1?
It helps to list the factors of ac=6, and then try adding some to get b=7.
Factors of 6 include 1, 2, 3 and 6.
1 and 6 add to 7, and 6×1=6.
Step 2: Rewrite the middle with those numbers:
Rewrite 7x with 6x and 1x:
2x^2 + 6x + x + 3
Step 3: Factor the first two and last two terms separately:
The first two terms 2x^2 + 6x factor into 2x(x+3)
The last two terms x+3 don't actually change in this case
So we get:
2x(x+3) + (x+3)
Step 4: If we've done this correctly, our two new terms should have a clearly visible common factor.
In this case we can see that (x+3) is common to both terms, so we can go:
Start with: 2x(x+3) + (x+3)
Which is: 2x(x+3) + 1(x+3)
And so: (2x+1)(x+3)
Done!
Check: (2x+1)(x+3) = 2x2 + 6x + x + 3 = 2x2 + 7x + 3 (Yes)
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