Answer:
I agree with daniel
Step-by-step explanation:
Given the area of a rectangle expressed as;
A(x) = 2x²+10x+12
On factorizing;
A(x) = 2x²+6x+4x+12
A(x) = 2x(x+3)+4(x+3)
A(x) = (x+3)(2x+4)
since A(x) = l(x)w(x)
Hence the legnth and width of the rectangle are 2x+4 and x+3.
Also A(x) = 2x²+6x+4x+12 can be factorized as;
A(x) = 2x²+4x+6x+12
A(x) = 2x(x+2) + 6(x+2)
A(x) = 2x+6(x+2)
Therefore I agree with Daniel. The factor differs due to the difference in arrangement of 4x and 6x in the expression. Precedence of values affects the final factors
