Answer:
[tex]let \: number \: of \: rides \: be \: \: n \\ let \: cost \: be \: \: c \\ n \: \alpha \: c \\ n = kc \\ k \: is \: a \: costant \: of \: proportionality \\ when \: n = 1. \: \: c = 2 \\ 1 = (k \times 2) \\ k = \frac{1}{2} \\ therefore : \\ n = 0.5c[/tex]
Answer:
[tex]\huge\boxed{\sf x = 6 + 2y}[/tex]
Step-by-step explanation:
Let the total cost be x and number of rides be y
It costs $2 on each ride. So, the rides' cost will be:
=> Number of rides * One rides' cost
=> y * 2
=> 2 y
So, The total cost will be:
Total cost = Entrance cost + Rides' cost
Total cost = $6 + $2(Number of rides)
x = 6 + 2y
[tex]\rule[225]{225}{2}[/tex]
Hope this helped!
