drickah8 drickah8

22-05-2021
Mathematics

contestada

What is the value of cd in the equation 32cd=11cd-42?

a. -1/2
b. 1/2
c. 2
d. -2

Respuesta :

jimrgrant1 jimrgrant1

22-05-2021

Answer:

d

Step-by-step explanation:

Given

32cd = 11cd - 42 ( subtract 11cd from both sides )

21cd = - 42 ( divide both sides by 21 )

cd = - 2 → d

Answer Link

guersonpmp2e45m guersonpmp2e45m

22-05-2021

32cd = 11 cd − 42 : Subtract 11cd from both sides.

32cd = 11cd − 42
-11cd − 11cd
21c = −42

Divide both sides by 21.
21cd /21 = −42/21

cd = −2

Answer Link

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