Answer:
202
Step-by-step explanation:
First, we can find the conjugate of (-9 -11i)
Given a complex number a + bi, the conjugate would be a - bi.
So, the conjugate of -9 -11i is -9 + 11i.
Now, we multiply!
(-9-11i)(-9+11i)
This resembles the special product (a+b)(a-b) which multiplies out to a^2 - b^2
To apply this we subtract the square of the second number from the first.
(-9)^2 - (11i)^2
81 - 121i^2
i^2 is -1, so we can substitute it in:
81 + 121 = 202
