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If it requires 75.0mL of 0.500M NaOH to neutralize 165.0 mL of an hcl solution what is the concentration of the hcl solution

Respuesta :

Answer:

0.027 M HCl

Explanation:

The chemical equation of the neutralization is:

1 NaOH + 1 HCl -> 1 H2O + 1 NaCl

Because the ratio of NaOH and HCl is 1:1 you can use the M1V1=M2V2 formula.

(75 mL)(0.5 M NaOH) = (165 mL)(M HCl)

It requires 0.027 M HCl.

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