Respuesta :
Answer:
(C) 180.0 g of C6H12O6 dissolved in 500.0 mL of solution
Explanation:
Molarity is mole/volume.
1. Find the mass of C6H12O6 in 1 Liter of 2.0 solution
(2 mol C6H12O6 / L) * (180 g / mol C6H12O6) = 360 g C6H12O6
There are 360 g C6H12O6 in 1000 mL of solution
2. Compare the value you found in step 1 to each of the multiple choice answers.
180.0 g of C6H12O6 dissolved in 500.0 mL of solution is exactly proportional to 360 g C6H12O6 in 1000 mL of solution.
The preparation which produces a 2.0 M solution of C₆H₁₂O₆ is 180.0 g of C₆H₁₂O₆ dissolved in 500.0 mL of solution.
How molarity is calculated?
Molarity is defined as the number of moles of solute present in per liter of solution.
Moles of any substance will be calculated as :
n = W/M, where
W = given mass
M = molar mass
In the question given that molar mass of C₆H₁₂O₆ is 180 g/mole, and let we have produced the solution of 2 molarity by these amount in 1 liter i.e.
2 = n/1
n = 2 moles
Now by using these moles we can calculate the required mass of C₆H₁₂O₆ as:
2 = W/180
W = 360g
From this it is clear that for the preparation of 1 liter of solution of 2 molarity 360g of C₆H₁₂O₆ is required. So in 500mL of solution, 180 g of C₆H₁₂O₆ will use.
Hence, option (C) is correct i.e. 180.0 g of C₆H₁₂O₆ dissolved in 500.0 mL of solution.
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