Answer: [tex]12.82\ m/s[/tex]
Explanation:
Given
Mass of car [tex]m=991\ kg[/tex]
Force applied [tex]F=31,770\ N[/tex]
time period [tex]t=0.4\ s[/tex]
Acceleration associated with car
[tex]\Rightarrow a=\dfrac{F}{m}\\\\\Rightarrow a=\dfrac{31770}{991}\\\\\Rightarrow a=32.05\ m/s^2[/tex]
Acceleration is the change in velocity w.r.t time
[tex]\Rightarrow a=\dfrac{\Delta v}{\Delta t}\\\\\Rightarrow 32.05=\dfrac{\Delta v}{0.4}\\\\\Rightarrow \Delta v=12.82\ m/s[/tex]
thus, the change in velocity is [tex]12.82\ m/s[/tex]