Answer:
192[tex]\sqrt{3}[/tex] + 912 [tex]in^{2}[/tex]
Step-by-step explanation:
The area of a regular hexagon = [tex]\frac{3\sqrt{3} a^{2} }{2}[/tex] where a is the length of a side.
So. a = 8
Area of the hexagon = [tex]\frac{3\sqrt{3}*8^{2} }{2}[/tex] = [tex]\frac{3\sqrt{3} *64 }{2}[/tex] = [tex]96\sqrt{3}[/tex]
Area of one lateral face = 8(19) = 152
Area of 6 lateral faces = 6(152) = 912
Total surface area = 2([tex]96\sqrt{3}[/tex]) + 912 = 192[tex]\sqrt{3}[/tex] + 912 [tex]in^{2}[/tex]
Hope this helps.
