Answer:
The triple are: 48, 55 and 73
Step-by-step explanation:
Given
[tex](x^2 + y^2)^2 = (x^2 - y^2)^2 + (2xy)^2[/tex]
[tex]x = 8; y=3[/tex]
Required
The Pythagorean triple
We have:
[tex](x^2 + y^2)^2 = (x^2 - y^2)^2 + (2xy)^2[/tex]
Substitute: [tex]x = 8; y=3[/tex]
[tex](8^2 + 3^2)^2 = (8^2 - 3^2)^2 + (2*8*3)^2[/tex]
[tex](64 + 9)^2 = (64 - 9)^2 + (48)^2[/tex]
[tex](73)^2 = (55)^2 + (48)^2[/tex]
[tex]5329 = 5329[/tex]
Hence, the triple are: 48, 55 and 73
