The acceleration of gravity on Ganymede will be [tex]g=0.35\ \frac{m}{s^2}[/tex]
What will be the acceleration of gravity on Ganymede?
It is given that for a simple pendulum on Ganymede
Lenth= 1.00 m
the time period T= 10.5 sec
The formula for a time period of simple pendulum will be
[tex]T=2\pi\sqrt{\dfrac{l}{g} }[/tex]
By rearranging the formula
[tex]g=l\times (\dfrac{2\pi}{T} )^2[/tex]
[tex]g=1\times (\dfrac{2\pi}{10.5} )^2=0.3577\frac{m}{s^2}[/tex]
[tex]g=0.3577\ \frac{m}{s^2}[/tex]
Thus the acceleration of gravity on Ganymede will be [tex]g=0.35\ \frac{m}{s^2}[/tex]
To know more about simple pendulums follow
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