Answer:
Spring constant, k = 200 N/m
Explanation:
Given the following data;
Potential energy = 0.36 J
Extension, e = 6 cm
Conversion:
100 cm = 1 meters
6 cm = 6/100 = 0.06 meters
To find the spring constant;
Mathematically, the energy stored in a spring is given by the formula;
[tex] E = \frac {1}{2}kx^{2} [/tex]
Where;
E is the energy.
K is the spring constant.
x is the extension of the spring.
Substituting into the formula, we have;
[tex] 0.36 = \frac {1}{2}*k*0.06^{2} [/tex]
Cross-multiplying, we have;
[tex] 0.36 * 2 = 0.0036k [/tex]
[tex] 0.72 = 0.0036k [/tex]
[tex] k = \frac {0.72}{0.0036} [/tex]
Spring constant, k = 200 N/m
