Given m || n, find the value of x and y.
m(2y+19)
n(5x+28)(4x-11)

Answer:
[tex]m || n \\ (4x - 11) + (5x + 20) = 180 \\ 9x + 9 = 180 \\ 9(x + 1) = 180 \\ x + 1 = 20 \\ x = 19 \\ \\ then \\ (4x - 11) = (2y + 19) \\ (4 \times 19 - 11) = (2y + 19) \\ 65 = 2y + 19 \\ 2y = 46 \\ y = 23[/tex]