Answer:
[tex]p=10\:\text{kgm/s}},\\v_f=1\:\text{m/s}[/tex]
Explanation:
From Newton's 2nd Law, we have [tex]\Sigma F=ma[/tex]. We can use this to find the acceleration of object after 20 N (force) is applied to the 10 kg object.
Substituting given values, we have:
[tex]\Sigma F=ma, \\20=10a,\\a=\frac{20}{10}=2\:\mathrm{m/s^2}[/tex]
Now that we have acceleration, we can find the final velocity of object (after 0.5 seconds) using the following kinematics equation:
[tex]v_f=v_i+at[/tex], where [tex]v_f[/tex] is final velocity, [tex]v_i[/tex] is initial velocity, [tex]a[/tex] is acceleration, and [tex]t[/tex] is time.
Solving for final velocity:
[tex]v_f=0+2\cdot 0.5,\\v_f=\boxed{1\:\text{m/s}}[/tex]
The momentum of an object is given as [tex]p=mv[/tex]. Since we've found the final velocity and mass stays constant, we have:
[tex]p=10\cdot 1=\boxed{10\:\text{kgm/s}}[/tex]
