need cos A and tan A asap please

Answer:
[tex]\sin A=\frac{12}{37},\\\\\cos A=\frac{35}{37},\\\\\tan A=\frac{12}{35}[/tex]
Step-by-step explanation:
In a right triangle only, the sine of an angle is equal to the angle's opposite side divided by the hypotenuse of the triangle. (o/h)
The cosine of the angle is equal to the angle's adjacent side divided by the hypotenuse of the triangle. (a/h)
The tangent of the angle is equal to angle's opposite side divided by the adjacent side. (o/a)
In this case, angle A's opposite side is 12, its adjacent side is 35, and the hypotenuse is 37 (o=12, a=35, h=37).
Thus we have:
[tex]\sin A=\frac{12}{37},\\\\\cos A=\frac{35}{37},\\\\\tan A=\frac{12}{35}[/tex]
Answer:
Step-by-step explanation:
sin A=opposite/hypotenuse=12/37
cos A=adjacent/hypotenuse=35/37
tan A=opposite/adjacent=12/35