Find the sum of the first eight terms of a geometric series is the fourth term of 25 in the constant ratio is 3/5 . Answer your answer as a decimal rounded to two places

Respuesta :

25 = a1(1- (0.6)⁴)/(1-0.6)

25 = a1 (1- 0.13)/(0.4)

10 = a1(0.87)

a1 = 11.49

S8 = 11.49(1- (0.6)^8)/(1-0.6)

= 11.49(1-0.017)(1-0.6)

= 11.49(0.983)/0.4

= 28.24

The sum of the first eight terms of the given geometric series is; 28.24

How to find the sum of a geometric series?

We are told that the sum of the first four terms of the geometric series is 25. Thus, formula for sum of n terms of a geometric series is;

Sₙ = a(1 - rⁿ)/(1 - r)

where;

a is first term

r is common ratio

Thus;

25 = a(1 - (0.6)⁴)/(1 - 0.6)

25 = a(1 - 0.13)/(0.4)

10 = 0.87a

a = 11.49

Thus, sum of the first 8 terms of the series is;

S₈ = 11.49(1 - 0.6⁸)/(1 - 0.6)

S₈ = 11.49(1 - 0.017)(1 - 0.6)

S₈ = 28.24

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