Answer:
177 mmHg
Explanation:
Given that:
The sample of a gas is with Pressure (1) [tex]P_1[/tex] = 500 mmHg
The initial temperature [tex]T_1[/tex] = 773 K
The final temperature [tex]T_2[/tex] = 273 K
Using ideal gas equation:
[tex]\dfrac{P_1}{T_1} = \dfrac{P_2}{T_2} \\ \\ \dfrac{500}{773} = \dfrac{P_2}{273} \\ \\ (136500) = 773 \times P_2 \\ \\ P_2 = \dfrac{136500}{773} \\ \\ P_2 = 176.58 \ mmHg \\ \\ \simeq 177 mmHg[/tex]
