gabrielangel1033 gabrielangel1033

24-05-2021
Mathematics

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In ΔBCD, the measure of ∠D=90°, the measure of ∠B=26°, and DB = 48 feet. Find the length of BC to the nearest tenth of a foot.

The length of BC Is ___ ft.

Respuesta :

29-05-2021

Answer:

98.4 feets

Step-by-step explanation:

To obtain BC

we could make use of B as angle, the apply the trigonometric relation :

Tan B =adjacent / hypotenus

Tan B = DB / BC

Tan 26 = 48 / BC

0.4877325 = 48 / BC

BC = 48 / 0.4877325

BC = 98.4 feets

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