Answer:
112.625 mL
Explanation:
Applying,
ML = M'L'.................... Equation 1
Where M = Initial molarity or concentration of calcium chloride, L = initial volume of calcium chloride, M' = Final molarity of calcuim chloride, L' = Final volume of calcuim chloride.
make L the subeject of the equation
L = M'L'/M................ Equation 2
From the question,
Given: M = 1.60 mol/L, M' = 0.34 mol/L, L' = 530 mL
Substitute these values into equation 2
L = (0.34×530)/1.60
L = 112.625 mL
