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If an arrow is shot upward on the moon with a velocity of 50 m/s, its height (in meters) after t seconds is given by H = 50t − 0.83t^2.

Respuesta :

MrRoyal

Answer:

The velocity is: 48.34m/s

Step-by-step explanation:

Given

[tex]u = 50m/s[/tex] --- initial velocity

[tex]h = 50t - 0.83t^2[/tex]

Required

The velocity after 1 second

We have:

[tex]h = 50t - 0.83t^2[/tex] and [tex]t = 1[/tex]

Differentiate

[tex]h' = 50 - 1.66t[/tex]

We have that:

[tex]v = h'[/tex]

So, the equation becomes

[tex]v = 50 - 1.66t[/tex]

Substitute 1 for t

[tex]v = 50 - 1.66*1[/tex]

[tex]v = 50 - 1.66[/tex]

[tex]v = 48.34[/tex]

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