Answer:
His standardized z-score is [tex]Z = \frac{1355 - \mu}{\sigma}[/tex], in which [tex]\mu[/tex] is the mean price of rents and [tex]\sigma[/tex] is the standard deviation for price of rents.
Step-by-step explanation:
Z-score:
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Johns rent is $1,355.
This means that [tex]X = 1355[/tex]
What is his standardized z-score
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{1355 - \mu}{\sigma}[/tex]
His standardized z-score is [tex]Z = \frac{1355 - \mu}{\sigma}[/tex], in which [tex]\mu[/tex] is the mean price of rents and [tex]\sigma[/tex] is the standard deviation for price of rents.